[Dresden-pm] Frage zu PAM

[Hagen Paul Pfeifer]

* Hans-Dietrich Kirmse | 2005-12-14 21:26:57 [+0100]:

>Das angegebene Beispiel gibt mir schon rätsel auf:
>
>   use Authen::PAM;
>
>   $login_name = getpwuid($<);
>
>   pam_start("passwd", $login_name, $pamh);
>   pam_chauthtok($pamh);
>   pam_end($pamh);

#include <security/pam_appl.h>
#include <security/pam_misc.h>
#include <stdio.h>

static struct pam_conv conv = {
    misc_conv,
    NULL
};

int main(int argc, char *argv[])
{
    pam_handle_t *pamh=NULL;
    int retval;
    const char *user="nobody";

    if(argc == 2) {
        user = argv[1];
    }

    if(argc > 2) {
        fprintf(stderr, "Usage: check_user [username]\n");
        exit(1);
    }

    retval = pam_start("check_user", user, &conv, &pamh);
        
    if (retval == PAM_SUCCESS)
        retval = pam_authenticate(pamh, 0);    /* is user really user? */

    if (retval == PAM_SUCCESS)
        retval = pam_acct_mgmt(pamh, 0);       /* permitted access? */

    /* This is where we have been authorized or not. */

    if (retval == PAM_SUCCESS) {
        fprintf(stdout, "Authenticated\n");
    } else {
        fprintf(stdout, "Not Authenticated\n");
    }

    if (pam_end(pamh,retval) != PAM_SUCCESS) {     /* close Linux-PAM */
        pamh = NULL;
        fprintf(stderr, "check_user: failed to release authenticator\n");
        exit(1);
    }

    return ( retval == PAM_SUCCESS ? 0:1 );       /* indicate success */
}

... sollte helfen ;-)


>Mit freundlichen Grüßen aus Thüringen
>Hans-Dietrich

HGN (mit freundlichen Gruss aus dem Schwarzwald)