[Chicago-talk] scalar question
Jay Strauss
me at heyjay.com
Mon Jan 31 14:12:05 PST 2011
Yea I know one
@a = split(/\-|\./,$fld1); # or something
Sent from my iPhone
On Jan 31, 2011, at 3:40 PM, Richard Reina <richard at rushlogistics.com> wrote:
> I know I should no this, but I don't and was wondering if someone could enlighten me. I have some scalars that represent filenames and look like this
>
> my $fl1=3321-1.pdf
> my $fl2=3321-2.pdf
> my $fl3=3432-1.pdf
>
> I can get everything before the "-" like this:
> $fl2=~s/\-.*//; # get the root of the filename
>
> but how can I do it without changing the contents of the original scalar? I'd like to put the result directly in a new scalar.
>
> $root_name= $f12=~s/\-.*//; # get the root of the filename
>
> Thanks.
> --
> Richard Reina
> Rush Logistics, Inc.
> Watch our 3 minute movie:
> http://www.rushlogistics.com/movie
>
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