SPUG: Where is grep's return value?

[Chris Wilkes]

On Tue, Sep 10, 2002 at 06:27:32PM -0400, Orr, Chuck  (NOC) wrote:
> Hello,
> 
> I have something that looks like this:
> 
> if (grep("$KEY",EXISTING)){
> 
> In the event that this is true, I want to print the data that makes it true.
> In other words, I want to print the line from EXISTING that contains the
> pattern from the variable $KEY.  The problem I am having is figuring out
> where that line is.  Is it stored in a variable I don't know about?  If not,
> how can I obtain this data?  I realize this is a pretty basic question, but
> I am having a tough time finding the answer and I need to get this done.
> Any suggestions/help would be greatly appreciated.

You should capture the output of grep into an array:

  @a = qw(one two three four twenty);
  if (@found = grep (/tw/, @a)) {
    print "Found: @found\n";
  } else {
    print "Didn't find\n";
  }

Chris

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