SPUG: Rebuked...

[Andrew Sweger]

On Jan 4, 2000 @ 11:09am, Steve Laybourn wrote:

> >	sub Cur {
> >	    my( $ix ) = shift;
> 
> ---Let local variable $ix equal the first element of the default array @_, 
> which in this case also equals $_. Hmmm, clever, that. How would you handle 
> more than one element going in to the array? @_[0], at _[1], etc.?

Time for a little more grabbing and shaking. $_ has nothing to do with @_
(other than sharing an entry in the symbol table). $_[0] is the scalar
contained in the first (or zeroth if you prefer) element of the @_ array.
@_[0] refers to an array slice, albeit containing a single element (a list
of one scalar).

-- 
 Andrew Sweger <andy at n2h2.com>    N2H2, Incorporated
                                  900 Fourth Avenue, Suite 3400
 No thanks, I'll just have the    Seattle WA 98164-1059
     Linux with a side of Perl    http://www.n2h2.com/  (206) 336-2947



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