parsing
Chris Radcliff
chris at velocigen.com
Wed May 3 17:51:27 CDT 2000
~sdpm~
Steve Meier wrote:
> can anyone help me with regular expressions!!
>
> Here is the string: 4129280 bytes sent in 3.62 seconds (1142.26
> Kbytes/sec)
>
> I need: 1142.26 out of it.
>
<perl>
my $string = '4129280 bytes sent in 3.62 seconds (1142.26 Kbytes/sec)';
my $result;
if ($string =~ /\((.+?)\s/) {
$result = $1;
}
print qq{The result is $result.\n};
</perl>
Basically, you're looking for stuff between the first ( and the next
space after that. By enclosing it in parentheses, Perl stores it in $1;
if you had another set of parentheses the result would be stored in $2,
etc.
~chris
~sdpm~
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