int(rand() + 1), int(rand()) +1, and hashes

Russ Schnapp rlssdpm at
Sun Jul 16 11:49:59 CDT 2000


> perl converted our interger to a floating point before performing 
> our arithmetic operation.

Well, all I can say is that this is a VERY counter-intuitive result.  

So, what's the rule?  All PERL arithmetic ops are carried out in 
floating point?  Yikes!

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