[Purdue-pm] Perl 6 regex question
mark at purdue.edu
Sat Jan 24 18:38:59 PST 2009
The following match regex works as expected
$s ~~ m/
(abc) # match and capture as $0
(def) # match and capture as $1
.+? # match one or more characters
$1 # match previously captured $1
$0 # match previously captured $0
I don't know if the following can be done with
% p6 --version
This is Rakudo Perl 6, revision 0 built on parrot 0.8.1
Copyright 2006-2008, The Perl Foundation.
I'd like to change the regex to do the following.
Instead of (abc) I'd like to have $a to be 'abc'
and use $a instead of 'abc'.
Instead of $1 I'd like to have it match $1 but
with the characters in reverse order.
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