[Nh-pm] Regexp help
Paul Lussier
pll at lanminds.com
Fri Feb 28 15:35:07 CST 2003
In a message dated: 27 Feb 2003 16:34:43 EST
Kevin D. Clark said:
>How about this instead?:
>
> (?:[[:xdigit:]]{2}:){5}[[:xdigit:]]{2}
Okay, I've stared at this until my brain hurts, and I can't quite be
sure I understand what's going on here. I think I've got it, but I'm
not sure, so please correct me where I'm wrong :)
First we've got:
( gobbldeygook ) more_gobbledeygook
The stuff within the parens will be saved as $1, correct?
Then, we have within the ()'s:
?:[[:xdigit:]]{2}:
I'm a little lost onthe '?:' but the '[[:xdigit:]]{2}:' I'm pretty
sure is "Any hex digit twice followed by a :".
Now, the '?:', according to perldoc perlre states:
"(?:pattern)"
"(?imsx-imsx:pattern)"
This is for clustering, not capturing; it groups
subexpressions like "()", but doesn't make back-
references as "()" does.
So, I'm assuming that this means the match isn't assigned to one the
the $digit vars?
Then we've got that mess 5 times, followed by a 2 more hex digits, right?
Okay, I think that makes sense. And, if I place the *entire* thing
into ()s, I get $1 assigned to that?
Thanks,
--
Seeya,
Paul
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