LPM: Test / question on date stuff
David Hempy
hempy at ket.org
Wed Feb 9 13:18:09 CST 2000
At 07:33 AM 2/9/2000 -0800, you wrote:
>It of course returns the date just like I want it
>(02/09/2000). So what code do I issue to get 28 days
>from now added onto the day and get the correct
>rollaround. (ie when you add 28 above you get Feb 37th
>-ugg instead of the early part of March). Any help
>would be appreciated and go toward good karma.
>
time is expressed in seconds since the epoch. You can adjust a time (which
is actually date and time) by adding/subtracting seconds.
There are 86400 seconds in a day (60*60*24).
This code will increment a time by 28 days:
$mytime = time();
$mytime += 28 * 86400;
Hope this helps,
-dave
--
David Hempy
Internet Database Administrator
Kentucky Educational Television
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