[Chicago-talk] OPEN() conditional

Shawn Carroll shawn.c.carroll at gmail.com
Thu Jun 30 12:05:38 PDT 2011

Instead of a readdir or even attempting the open the file, just test
for it's existance ala:

my $file = -e $file1Path ? $file1Path: -e $file2Path ? $file2Path: die
'neither file avail';
open (my $FH, '<', $file) or die ' Cannot open $file: $!' ;

shawn.c.carroll at gmail.com
Perl Programmer
Soccer Referee

On Thu, Jun 30, 2011 at 13:46, Richard Reina <richard at rushlogistics.com> wrote:
> I am writing a script that among other things edits a file.  The file can be in one of two places (directories) so if the first open does not work I want it to try the open of the file in the alternative directory.  I know how to do open(F, "</blah/blah") || die or open(F, "</lbal") || warn; but I don't want the program to die but to try another directory.  Is there a way to do open() conditionals or do I need to use readdir first to see if the file exists?
> Thanks,
> Richard
> --
> Richard Reina
> Rush Logistics, Inc.
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