[Chicago-talk] string operator question.

[Richard Reina]

   Thank you Kent. Obviously I missed that.
>  
>  Chicago.pm chatter <chicago-talk at pm.org> wrote:  > On Sep 12, 2009, at 9:42 AM, Richard Reina <richard at rushlogistics.com> wrote:
 
>   > I think I've got it now. I found this:
>  
>  
>  if($mystring =~ m/(\d+)/) {
>     print "The first number is $1.";
>  }
>  
>  in a tutorial at http://www.somacon.com/p127.php
>  
>  and hacked it up so that my number gets the value
> of
>  
>  $number = $1
>  
>  and it works.
>  
>  However, I am confused by the representation of the
> scalar $1 I have never seen that before.  Can someone
> explain $1.  Or is it something that should not be
> explained but instead accepted at face value?
  It says on that page, right above your example:
>  

> Prints "The first digit is 2." In order to designate
> a pattern for extraction, one places parenthesis around
> the pattern. If the pattern is matched, it is returned
> in the Perl special variable called $1. If there are
> multiple parenthesized expressions, then they will
> be in variables $1, $2, $3, etc.

 > 
  
  
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