[Chicago-talk] string operator question.

[Richard Reina]

I think I've got it now. I found this:

$mystring = "[2004/04/13] The date of this article.";
if($mystring =~ m/(\d+)/) {
	print "The first number is $1.";
}

in a tutorial at http://www.somacon.com/p127.php

and hacked it up so that my number gets the value of

$number = $1 

and it works.

However, I am confused by the representation of the scalar $1 I have never seen that before.  Can someone explain $1.  Or is it something that should not be explained but instead accepted at face value?




---- Chicago.pm chatter <chicago-talk at pm.org> wrote:
>
> Thank you very much Andy.  Problem solved.
> ---- Chicago.pm chatter <chicago-talk at pm.org> wrote:
> >
> > 
> > On Sep 12, 2009, at 8:52 AM, Richard Reina wrote:
> > 
> > >    require "/usr/src/laundpad/ORD_processor.pl";
> > >    my $result = process($number);
> > >
> > >
> > > snip
> > >
> > > #!/usr/bin/perl -w
> > > # ORD_processor.pl
> > >
> > > sub process {
> > >
> > > print "I will attempt to process " .  $number . "\n";
> > > chomp (my $XX = <STDIN>);
> > >
> > > }
> > 
> > You're not taking number as the arg to process().  You need
> > 
> >    my $number = shift;
> > 
> > xoxo,
> > Andy
> > 
> > --
> > Andy Lester => andy at petdance.com => www.theworkinggeek.com => AIM:petdance
> > 
> > 
> > 
> > 
> > 
> > 
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