[Brisbane-pm] Convert string to date in Perl

[David Bussenschutt]

I use Date::Manip all the time.   it rocks.
see http://search.cpan.org/~sbeck/DateManip-5.44/Manip.pod

use Date::Manip;

$date = ParseDate("25/02/1990 23:48:00");
$delta = ParseDateDelta("+ 6 minutes");
$new = DateCalc($date,$delta); 
# or alternate/shorthand:
$new =DateCalc("25/02/1990 23:48:00","+ 6 minutes"); 

# then output however you like.
print &UnixDate($new,"It is now %T on %b %e, %Y.");

-----Original Message-----
From: brisbane-pm-bounces+david.bussenschutt=qmtechnologies.com at pm.org
[mailto:brisbane-pm-bounces+david.bussenschutt=qmtechnologies.com at pm.org
]On Behalf Of Damian James
Sent: Wednesday, 31 January 2007 2:11 PM
To: Martin Jacobs
Cc: Brisbane Perl Group
Subject: Re: [Brisbane-pm] Convert string to date in Perl


Time::Local

Or roll you own regex, something like:

   my %date;
   $_ = '25/02/1990 23:48:00';
   @date{ qw/ day month year hour minute second/} = m<^(\d\d?)/(\d 
\d?)/(\d{4}) +(\d\d):(\d\d):(\d\d)>;
   $date{ minute } += 6;
   printf "%2d/%2d/%4d %2d:%2d:%2d", @date{ qw/ day month year hour  
minute second/};

Though use the module for maintainability.

Damian

On 31/01/2007, at 2:01 PM, Martin Jacobs wrote:

> Hi all,
>
> I would appreciate some help here.
>
> How do I convert a string to a date?
>
> Here's an example of the string...
>
> 25/02/1990 23:48:00
>
> I want to add on 6 minutes, so that the result is...
>
> 25/02/1990 23:54:00
>
> Thanks in advance.
>
> Regards,
> Martin Jacobs
> Visit my website...
> http://web.mac.com/martin_jacobs1
>
>
> _______________________________________________
> Brisbane-pm mailing list
> Brisbane-pm at pm.org
> http://mail.pm.org/mailman/listinfo/brisbane-pm

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