<br>But, $^ is assignable and, if set to the empty string, <br>invalidates /$^/ as a regex that won't match anything:<br><br>perl -wle '$^=''"; print "match" if "foo" =~/$^/'<br>
match<br><br>-- <br>Charles DeRykus<br><br><br><div class="gmail_quote">On Fri, Aug 21, 2009 at 11:12 PM, Michael R. Wolf <span dir="ltr"><<a href="mailto:MichaelRWolf@att.net">MichaelRWolf@att.net</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;"><div class="im"><br>
On Aug 19, 2009, at 12:38 AM, Ingy dot Net wrote:<br>
<br>
<blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
<br>
<br>
On Tue, Aug 18, 2009 at 10:33 PM, Steve Sandvik <<a href="mailto:ssandv@gmail.com" target="_blank">ssandv@gmail.com</a>> wrote:<br>
well, /$^/ seems like a plausible starting point. Or ending point.<br>
Or something. :-)<br>
<br>
Nope.<br>
<br>
$^ = "";<br>
$anything =~ /$^/;<br>
</blockquote>
<br>
<br></div>
I'm missing your point.<br>
<br>
If you mean to indicate that interpolation happens inside m//, and that $^ is an internal perlvar (with $FORMAT_TOP_NAME as a 'use English' equivalent), then it is *not* an empty string. Here's the one-liner to show that...<br>
<br>
$ perl -le 'print $^'<br>
STDOUT_TOP<br>
$<br>
<br>
But, perhaps I missed your intent.<br><font color="#888888">
<br>
-- <br></font><div><div></div><div class="h5">
Michael R. Wolf<br>
All mammals learn by playing!<br>
<a href="mailto:MichaelRWolf@att.net" target="_blank">MichaelRWolf@att.net</a><br>
<br>
<br>
<br>
<br>
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