SPUG:for help

[John Subaykan]

If you are already using an if statement to check the string with a regular 
expression, just use that to capture.  Like this:


if ($line =~ /^\s+(\d+)\s+(.+?)\s+(\d+)$/) {

    ($part1, $part2, $part3) = ($1,$2,$3);

}


John

----Original Message Follows----
From: "Liu, Zhu" <Liu.Zhu at mayo.edu>
To: "'spug-list at mail.pm.org'" <spug-list at mail.pm.org>
Subject: SPUG:for help
Date: Wed, 29 Jan 2003 22:19:57 -0600

Hi, everybody, I experienced a very stupid simple problem for three hours. I 
just want to extract three substrings from one string. In the beginning of 
the string there are two spaces  like
    207 MFSNLASDEQDSVRLLAV---EAC--VNIAQLLPQEDLEALVMPTLRQAAEDKSWRVRYM   261

My part code is
if( $line =~ /^\s+\d+.*\d$/)
{
	($part, $part2, $part3) = /\s+(\d+)\s(.*)\s+(\d+)/;
}

it always tells me "Use of uninitialized value in pattern match (m//)", so 
if I use the following codes
if( $line =~ /^\s+\d+.*\d$/)
{
	($emptypart, $start, $part, $end) = split /\s+/, $line, 4;
}

This time I can get the items.

So my question is why parentheses can't catch the substrings?

Thanks,
zhu liu

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