Subset regular expression substitution

[Nelson Ingersoll]

David,

    I agree with Keary.  "Nice and elegant!"  Thank you!

- Nelson ...

At 2/21/2002 11:46 AM, David R. Waddell wrote:
>Hi Nelson,
>There is another way that is probably more efficient than
>regular expressions for this. It also may be more understandable
>when you look at the code:
>
>while(<>){
>         substr($_,0,10) =~ tr/()/ /
>}
>continue{
>         print STDOUT
>}
>
>It only performs the tr on the first 10
>characters.
>
>all the best,
>david
>At 05:00 PM 2/13/02 -0700, Nelson Ingersoll wrote:
> >Greetings Fellow Mongers,
> >
> >    I have a string which may, or may not, have parenthesis somewhere in
> >the first 10 characters.  The string is always longer than 10
> >characters.  I want to substitute space for either "(" or ")" or
> >both.   Because that part of the string which beyond the tenth character is
> >descriptive text, I dare not change any parenthesis after the first 10
> >characters.  I understand the regex {$x =~ s/\(|\)/ /g;} matches any and
> >all occurrences of either the '(' or ')' characters and replaces any '(' or
> >')' with a space.
> >
> >    The issue is, can I force the substitution, "s/\(|\)/ /g", to only work
> >over the first 10 characters of $x rather than all characters?  Is this
> >possible in a regex?   If not, I can always sub-string wing it.
> >
> >    Your thoughts will be appreciated!
> >
> >- Nelson ...
> >
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