[Pdx-pm] Not a syntax error?

Michael G Schwern schwern at pobox.com
Mon May 2 16:16:13 PDT 2005

On Mon, May 02, 2005 at 03:57:08PM -0700, Steve Bonds wrote:
> -----
> #!/usr/local/bin/perl -w
> print "This is a line without a semicolon\n".
> exit 1;
> -----
> It almost seems like the print line uses string concatenation to
> absorb the exit line-- but it doesn't.  The exit line is executed
> properly and the above perl terminates with status 1, however the
> output from the print statement is never seen.
> This didn't generate a warning using perl 5.8.0.  Should it have?

Nope.  Think of it like this.

	my $return_from_exit = exit 1;
	print "This is a line without a semicolon\n". $return_from_exit;

The arguments to a function are evaluated *before* the function is
executed.  Thus exit(1) happens before print but since exit ends the
program the print never happens.

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