[Chicago-talk] scalar question

[Jay Strauss]

Yea I know one

@a = split(/\-|\./,$fld1); # or something 

Sent from my iPhone

On Jan 31, 2011, at 3:40 PM, Richard Reina <richard at rushlogistics.com> wrote:

> I know I should no this, but I don't and was wondering if someone could enlighten me.  I have some scalars that represent filenames and look like this
> 
> my $fl1=3321-1.pdf
> my $fl2=3321-2.pdf
> my $fl3=3432-1.pdf
> 
> I can get everything before the "-" like this:
> $fl2=~s/\-.*//; # get the root of the filename    
> 
> but how can I do it without changing the contents of the original scalar? I'd like to put the result directly in a new scalar.
> 
> $root_name= $f12=~s/\-.*//; # get the root of the filename    
> 
> Thanks.
> -- 
> Richard Reina
> Rush Logistics, Inc.
> Watch our 3 minute movie: 
> http://www.rushlogistics.com/movie
> 
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